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In a “lazy” language, we evaluate a function call f(e) by passing the unevaluated argument to the function body. If the value of the argument is needed, then it is evaluated as part of the evaluation of the body of f. For example, consider the function g deﬁned by
fun g(x,y) = if = x=0
else if x+y=0
In a lazy language, we evaluate the call g(3,4+2) by passing some representation of the expressions 3 and 4+2 to g. We evaluate the test x=0 by using the argument 3. If it were true, the function would return 1 without ever computing 4+2. Because the test is false, the function must evaluate x+y, which now causes the actual parameter 4+2 to be evaluated. Some examples of lazy functional languages are Miranda, Haskell, and Lazy ML; these languages do not have assignment or other imperative features with side effects.
If we are working in a pure functional language without side effects, then for any function call f(e1, e2), we can evaluate e1 before e2 or e2 before e1. Because neither can have side effects, neither can affect the value of the other. However, if the language is lazy, we might not need to evaluate both of these expression. Therefore, something can go wrong if we evaluate both expressions and one of them does not terminate.
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As Backus argues in his Turing Award lecture, an advantage of pure functional languages is the possibility of parallel evaluation. For example, in evaluating a function call f(e1, e2) we can evaluate both e1 and e2 in parallel. In fact, we could even start evaluating the body of f in parallel as well.
1.Assume we evaluate g(e1, e2) by starting to evaluate g, e1, and e2 in parallel, where g is the function deﬁned above. Is it possible that one process will have to wait for another to complete? How can this happen?
2.Now, suppose the value of e1 is zero and evaluation of e2 terminates with an error. In the normal (i.e., eager) evaluation order that is used in C and other common languages, evaluation of the expression g(e1, e2) will terminate in error. What will happen with lazy evaluation? Parallel evaluation?
3.Now, suppose the value of e1 is zero and evaluation of e2 terminates with an error. In the normal (i.e., eager) evaluation order that is used in C and other common languages, evaluation of the expression g(e1, e2) will terminate in error. What will happen with Parallel evaluation?
4.Suppose you want the same value, for every expression, as lazy evaluation, but you want to evaluate expressions in parallel to take advantage of your new pocket-sized multiprocessor. What actions should happen, if you evaluate g(e1, e2) by starting g, e1,and e2 in parallel, if the value of e1 is zero and evaluation of e2 terminates in an error?
5.Suppose now that the language contains side effects. What if e1 is z and e2 contains an assignment to z; can you still evaluate the arguments of g(e1, e2) in parallel? How? Or why not?
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